The water content of soil Test – it specified as the portion of water present in soil mass by its weight. the decision of the water content of the soil.
- Water Content of Soil – Test Procedure, Result & Report
- Specific Gravity of Soil Test With Sample Report
🌀Water Content of Soil Test Procedure, Result & Report
Water Content of Soil Test
🧡 Water Content of Soil 🤍
The water content of the soil is specified as the portion of water present in soil mass by its weight. Water content information is needed for most of the soil criterion estimation.
w =weight of dry soil
Water content is normally revealed in percent.
For much better outcomes, the minimum size of one of the most soil specimens needs to be approximate as given up Table -1. This information makes up with ASTM Test Designation D-2216.
Particle Size in the Soil (mm)
|U. S. Sieve
Mass of Soil Sample (g)
🧡1. Moisture can(s): 🤍
Moisture cans are available in different sizes [for example, 2-in. (50.S mm) diameter and % in. (22.2 mm) high, 3.5-in. (S8.9 mm) diameter and 2 in. (50.S mm) high).
🧡2. Oven with temperature control:🤍
For drying of soil, the temperature of the oven is kept between 105°C to 110°C. A higher temperature of the oven should be avoided by the burning of organic matters of soil.
The weight balance should have an accuracy of 0.01 gm for specimens having a mass of 200 g or less.
Procedure Water Content of Soil
1. Find out the weight empty container (W1)and also record the number.
2. Take a representative sample of soil in the container. Close the container with its cap to avoid loss of moisture.
3. Take the weight of the combined mass (g) of the closed container and moist soil (W2).
4. Remove the cap from the top of the can and place it on the bottom (of the can).
5. Put the container (Step 4) in the oven to dry the soil to a constant weight. In most cases, 24 hours of drying is enough.
6. Determine the combined mass (g) of the dry soil sample plus the can and its cap (W3).
Calculation Water Content of Soil:
1. Mass or Weight of Moisture = W2– W3
2. Weight of dry soil = W3– W1
3. Water Content =
W (%) = (W2– W3) * 100 ) x W3– W1
Calculate water to an accuracy of 0.1 % appropriate based on the size of the specimen.
A sample representative calculation is given in table – 2,
Description of Soil=_______________. Sample No_________
|Weight of container, W1||17.31||18.92||16.07|
|Weight of container + Wet Soil, W2 (g)||43.52||52.19||39.43|
|Weight of Container + Dry Soil, W3 (g)||39.86||47.61||36.13|
|Weight of Moisture, W2– W3 (g)||3.66||4.58||3.30|
|Weight of dry Soil, W3– W1 (g)||22.55||28.69||20.06|
|Moisture Content, w (%)= (W2– W3) * 100
Take Average of above three results =(16.2 + 16.0 + 16.5)/3 = 16.23 %
The Final Water Content of Soil is 16.23%
1) Most natural soils, which have gravel and sandy in nature, may have water contents up to about 15 to 20%. In natural silty or clayed soil water content can be found about 50 to 80% can be found. However, in highly organic soil and peat with water contents up to about 500% is not uncommon.
2) Different organic soil particles get decompose during oven drying at 110°C. An oven heating temperature of 110° may be too high for soils containing gypsum, as this material slowly dehydrates. As per ASTM, a drying temperature of 60°C is more appropriate for such soils.
3) It is recommended the Cooling the dry soil after oven drying (Step 5) in a desiccator. It helps to prevents the absorption of moisture from the atmosphere.
Some standard values for various types of natural soils in a saturated state are shown in Table 2
Water Content in Saturated State (%)
|Loose uniform sand||25-30|
|Dense uniform sand||12-16|
|Loose angular-grained silty sand||25|
|Dense angular-grained silty sand||15|
|Soft organic clay||80-130|